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(A) The orbital magnetic moment $\vec{m}$ of an electron revolving in a circular orbit is given by $\vec{m} = I \vec{A}$,where $I$ is the current and

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$m$ and $L$ are in opposite directions perpendicular to the plane of the orbit.

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(A) The orbital magnetic moment $\vec{m}$ of an electron revolving in a circular orbit is given by $\vec{m} = I \vec{A}$,where $I$ is the current and $\vec{A}$ is the area vector. Since the electron is negatively charged,the direction of the equivalent current $I$ is opposite to the direction of the electron's motion. By the right-hand rule,the direction of $\vec{m}$ is perpendicular to the plane of the orbit.The angular momentum $\vec{L}$ of the electron is given by $\vec{L} = \vec{r} 	imes \vec{p}$,where $\vec{p} = m_e \vec{v}$ is the linear momentum. According to the right-hand rule for the cross product,the direction of $\vec{L}$ is also perpendicular to the plane of the orbit.Because the electron has a negative charge,the direction of the magnetic moment $\vec{m}$ is opposite to the direction of the angular momentum $\vec{L}$. Therefore,$\vec{m}$ and $\vec{L}$ are in opposite directions perpendicular to the plane of the orbit.

An electron is moving in an orbit around the nucleus in an atom. Let $m$ be the orbital magnetic moment and $L$ be the angular momentum of the electron,then

Similar Questions

What is orbital magnetic moment? And what is intrinsic magnetic moment?

Write the equation for the orbital magnetic moment of an electron rotating about the nucleus in an atom.

The magnetic moment of an electron $(e)$ revolving in an orbit around a nucleus with an orbital angular momentum $\vec{L}$ is given by:

If the angular momentum of an electron is $\vec{J}$,then the magnitude of the magnetic moment will be:

The magnetic moment of a revolving electron of charge $e$ and mass $m$ in terms of the angular momentum $L$ of the electron is:

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