An electron with speed $v$ and a photon with speed $c$ have the same $de-Broglie$ wavelength. If the kinetic energy and momentum of the electron are $E_{e}$ and $p_{e}$ and that of the photon are $E_{ph}$ and $p_{ph}$ respectively,which of the following is correct?
- A$\frac{E_{e}}{E_{ph}} = \frac{2c}{v}$
- B$\frac{E_{e}}{E_{ph}} = \frac{v}{2c}$
- C$\frac{p_{e}}{p_{ph}} = \frac{2c}{v}$
- D$\frac{p_{e}}{p_{ph}} = \frac{v}{2c}$
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