An element has d^5 configuration. The total n | vedclass

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(B) The total number of electron exchanges is given by the formula $\frac{n(n-1)}{2}$,where $n$ is the number of electrons with the same spin in the s

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$10$

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(B) The total number of electron exchanges is given by the formula $\frac{n(n-1)}{2}$,where $n$ is the number of electrons with the same spin in the same subshell.For a $d^5$ configuration,all $5$ electrons have the same spin (parallel spin) in $5$ different orbitals.Substituting $n = 5$ into the formula:$	ext{Total exchanges} = \frac{5(5-1)}{2} = \frac{5 	imes 4}{2} = \frac{20}{2} = 10$.

An element has $d^5$ configuration. The total number of electron exchanges possible for it is

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