An element in +2 oxidation state has 24 elect | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electronic configuration of an element with atomic number $Z$ in $+2$ oxidation state is equivalent to an atom with $Z-2$ electrons.Given $Z-2

Vedclass · Accepted Answer

$26$ and $4$

Vedclass · Answer

(B) The electronic configuration of an element with atomic number $Z$ in $+2$ oxidation state is equivalent to an atom with $Z-2$ electrons.Given $Z-2 = 24$, the atomic number $Z = 26$. The element is $Fe$.The ground state electronic configuration of $Fe$ $(Z=26)$ is $[Ar] 3d^6 4s^2$.The configuration of $Fe^{2+}$ is $[Ar] 3d^6$.In the $3d^6$ configuration, the electrons are distributed in $5$ orbitals of $d$-subshell according to Hund's rule: $d_{xy}^2, d_{yz}^1, d_{zx}^1, d_{x^2-y^2}^1, d_{z^2}^1$.Thus, there are $4$ unpaired electrons.

An element in $+2$ oxidation state has $24$ electrons. The atomic number of the element and the number of unpaired electrons in it respectively are

Similar Questions

Which one of the following electronic arrangements is absurd?

The total number of electrons present in all the $p$-orbitals of bromine is

The number of angular and radial nodes in $3p$ orbital respectively are

The set of quantum numbers for the $19^{th}$ electron in chromium $(Cr)$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module