An element with BCC structure has an edge len | vedclass

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(A) Given: Edge length $a = 500 \ pm = 500 	imes 10^{-10} \ cm = 5 	imes 10^{-8} \ cm$. Density $d = 4 \ g \ cm^{-3}$. For $BCC$ structure, the numb

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$150 \ g \ mol^{-1}$

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(A) Given: Edge length $a = 500 \ pm = 500 	imes 10^{-10} \ cm = 5 	imes 10^{-8} \ cm$. Density $d = 4 \ g \ cm^{-3}$. For $BCC$ structure, the number of atoms per unit cell $Z = 2$. The formula for density is $d = \frac{Z 	imes M}{N_A 	imes a^3}$. Rearranging for molar mass $M$: $M = \frac{d 	imes N_A 	imes a^3}{Z}$. Substituting the values: $M = \frac{4 	imes 6.022 	imes 10^{23} 	imes (5 	imes 10^{-8})^3}{2}$. $M = \frac{4 	imes 6.022 	imes 10^{23} 	imes 125 	imes 10^{-24}}{2}$. $M = 2 	imes 6.022 	imes 125 	imes 10^{-1} = 150.55 \ g \ mol^{-1} \approx 150 \ g \ mol^{-1}$.

An element with $BCC$ structure has an edge length of $500 \ pm$. If its density is $4 \ g \ cm^{-3}$, find the atomic mass of the element.

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