An equiconvex glass lens (a) has a focal leng | vedclass

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(D) When an equiconvex lens is cut along the principal axis,each half retains the same focal length $f$ and power $P$ as the original lens because the

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(D) When an equiconvex lens is cut along the principal axis,each half retains the same focal length $f$ and power $P$ as the original lens because the radii of curvature $R_1$ and $R_2$ of the refracting surfaces remain unchanged.In the configuration shown in figure $(c)$,the two halves are placed such that one is inverted relative to the other. If the first half acts as a converging lens with power $P$,the second half,being inverted,acts as a diverging lens with power $-P$ for the same optical path.The total power of the combination is $P_{net} = P_1 + P_2 = P + (-P) = 0$.

An equiconvex glass lens $(a)$ has a focal length $f$ and power $P$. It is cut into two symmetrical halves $(b)$ by a plane containing the principal axis. The two pieces are recombined as shown in figure $(c)$. The power of the new combination is

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