An ester (A) with molecular formula C_9H_{10} | vedclass

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(A) The ester $(A)$ is $C_6H_5COOC_2H_5$ (ethyl benzoate).Reaction with excess $CH_3MgBr$ proceeds as follows:$C_6H_5COOC_2H_5 + 2CH_3MgBr \rightarrow

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$C_6H_5COOC_2H_5$

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(A) The ester $(A)$ is $C_6H_5COOC_2H_5$ (ethyl benzoate).Reaction with excess $CH_3MgBr$ proceeds as follows:$C_6H_5COOC_2H_5 + 2CH_3MgBr \rightarrow C_6H_5-C(OH)(CH_3)_2 + Mg(OC_2H_5)Br + Mg(OH)Br$.Dehydration with $H_2SO_4$ gives the olefin $(B)$: $C_6H_5-C(CH_3)=CH_2$ ($2$-phenylpropene).Ozonolysis of $(B)$ yields $C_6H_5COCH_3$ (acetophenone) and $HCHO$.Acetophenone $(C_6H_5COCH_3)$ contains a $CH_3CO-$ group and thus gives a positive iodoform test.

An ester $(A)$ with molecular formula $C_9H_{10}O_2$ was treated with excess of $CH_3MgBr$ and the complex so formed was treated with $H_2SO_4$ to give an olefin $(B)$. Ozonolysis of $(B)$ gave a ketone with molecular formula $C_8H_8O$ which shows positive iodoform test. The structure of $(A)$ is

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If the general formula of oxime and semicarbazone is $C=N-Z$,what is '$Z$' in oxime $(I)$ and semicarbazone $(II)$?

Identify the group $R$ in the following reaction:
$CH_3CH_2CHO \xrightarrow[2. H_3O^+]{1. RMgBr} CH_3CH_2CH(OH)CH_2CH_3$
$R$ is:

Tollen's reagent is

The reaction sequence is as follows:
$HOOC-CH_2-CH_2-CH_2-CH_2-COOH$ $\xrightarrow[BaCO_3]{\Delta} A$ $\xrightarrow{NH_2-NH_2} B$ $\xrightarrow[KOH]{\text{heat}} C$
The final product $(C)$ obtained is:

Which of the following carbonyl compounds does $NOT$ undergo aldol condensation?

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