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(C) The formula of dichlorotetraaqua-chromium$(III)$ chloride is $[Cr(H_2O)_4Cl_2]Cl$.In this coordination compound,only the chloride ion outside the

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$0.001$

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(C) The formula of dichlorotetraaqua-chromium$(III)$ chloride is $[Cr(H_2O)_4Cl_2]Cl$.In this coordination compound,only the chloride ion outside the coordination sphere is ionizable.$[Cr(H_2O)_4Cl_2]Cl ightarrow [Cr(H_2O)_4Cl_2]^+ + Cl^-$One mole of the complex yields $1 \ mole$ of $Cl^-$ ions,which reacts with $AgNO_3$ to form $1 \ mole$ of $AgCl$ precipitate.Number of moles of complex $= M 	imes V_{(L)} = 0.01 	imes 0.1 = 0.001 \ mol$.Therefore,the number of moles of $AgCl$ precipitated is $0.001 \ mol$.

An excess of $AgNO_3$ is added to $100 \ mL$ of a $0.01 \ M$ solution of dichlorotetraaqua-chromium$(III)$ chloride. The number of moles of $AgCl$ precipitated would be

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