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(B) Let the mass of the ice be $M_i$ and the mass of the glass ball be $M_g$. Initially,the ice block with the glass ball floats in water. According t

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Falls

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(B) Let the mass of the ice be $M_i$ and the mass of the glass ball be $M_g$. Initially,the ice block with the glass ball floats in water. According to the law of floatation,the total weight of the system is equal to the weight of the displaced water. Total weight $W = (M_i + M_g)g$. The volume of water displaced initially is $V_1 = \frac{M_i + M_g}{\rho_w}$,where $\rho_w$ is the density of water. When the ice melts,the ice turns into water with volume $V_{iw} = \frac{M_i}{\rho_w}$. The glass ball sinks to the bottom. The volume of water displaced by the glass ball is $V_g = \frac{M_g}{\rho_g}$,where $\rho_g$ is the density of the glass ball. Since the glass ball is denser than water $(\rho_g > \rho_w)$,the volume of water displaced by the submerged glass ball is $V_g = \frac{M_g}{\rho_g} The final volume of the water level corresponds to $V_2 = V_{iw} + V_g = \frac{M_i}{\rho_w} + \frac{M_g}{\rho_g}$. Comparing $V_1$ and $V_2$,since $\frac{M_g}{\rho_g} Therefore,the level of water falls.

An ice block contains a glass ball. When the ice melts within a vessel containing water,the level of the water

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