An ideal gas expands according to the law P^2 | vedclass

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(A) Given the process law: $P^2 V = K$ (where $K$ is a constant).Using the ideal gas equation $PV = nRT$, we can write $P = \frac{nRT}{V}$.Substitutin

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Increases continuously

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(A) Given the process law: $P^2 V = K$ (where $K$ is a constant).Using the ideal gas equation $PV = nRT$, we can write $P = \frac{nRT}{V}$.Substituting this into the given law: $(\frac{nRT}{V})^2 V = K \Rightarrow \frac{n^2 R^2 T^2}{V^2} V = K \Rightarrow T^2 V^{-1} = 	ext{constant}$.This implies $T^2 \propto V$.Since the gas is expanding, the volume $V$ increases.As $V$ increases, $T^2$ must increase, which means the temperature $T$ of the gas increases.The internal energy $U$ of an ideal gas is given by $U = n C_V T$.Since $U \propto T$, as the temperature $T$ increases, the internal energy $U$ of the gas also increases continuously.

An ideal gas expands according to the law $P^2 V = \text{constant}$. The internal energy of the gas

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