An ideal gas is heated from 27^{circ}C to 627 | vedclass

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Question

(A) According to Charles's Law, for a fixed mass of an ideal gas at constant pressure, the volume is directly proportional to its absolute temperature

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(A) According to Charles's Law, for a fixed mass of an ideal gas at constant pressure, the volume is directly proportional to its absolute temperature: $V \propto T$ or $\frac{V_1}{T_1} = \frac{V_2}{T_2}$.Given:Initial temperature $T_1 = 27^{\circ}C = 27 + 273 = 300 	ext{ K}$.Final temperature $T_2 = 627^{\circ}C = 627 + 273 = 900 	ext{ K}$.Initial volume $V_1 = 4 	ext{ m}^3$.Substituting the values in the formula:$\frac{4}{300} = \frac{V_2}{900}$.$V_2 = 4 	imes \frac{900}{300} = 4 	imes 3 = 12 	ext{ m}^3$.Therefore, the new volume of the gas is $12 	ext{ m}^3$.

An ideal gas is heated from $27^{\circ}C$ to $627^{\circ}C$ at constant pressure. If initial volume of gas is $4 \text{ m}^3$, then the new volume of the gas will be (in $\text{ m}^3$)

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