An ideal transformer converts $220 \ V$ $AC$ to $3.3 \ kV$ $AC$ to transmit a power of $4.4 \ kW$. If the primary coil has $600$ turns,then the alternating current in the secondary coil is:

  • A
    $\frac{5}{3} \ A$
  • B
    $\frac{1}{4} \ A$
  • C
    $\frac{4}{3} \ A$
  • D
    $\frac{2}{3} \ A$

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