(A) According to the law of conservation of mechanical energy,the potential energy at the top is converted into kinetic energy at the bottom.Since bot

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Both will reach the ground with the same speed.

(A) According to the law of conservation of mechanical energy,the potential energy at the top is converted into kinetic energy at the bottom.Since both objects start from the same height $h$,their initial potential energy is $mgh$.At the bottom,this energy is converted into kinetic energy: $mgh = \frac{1}{2}mv^2$.Solving for speed $v$,we get $v = \sqrt{2gh}$.Since $v$ depends only on $g$ and $h$,both objects will reach the ground with the same speed.Therefore,the correct option is $A$.

Class 11 Physics Work, Energy, Power and Collision Work Energy Theorem and Conservation of Mechanical Energy

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An object starts sliding on a frictionless inclined plane,and from the same height,another object starts falling freely. Which of the following statements is correct?

A
Both will reach the ground with the same speed.
B
Both will reach the ground with the same acceleration.
C
Both will reach the ground in the same time.
D
None of the above.

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Work, Energy, Power and Collision

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Work Energy Theorem and Conservation of Mechanical Energy

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What can be said about the law of conservation of energy?

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An object starts sliding on a frictionless inclined plane,and from the same height,another object starts falling freely. Which of the following statements is correct?

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$A$ body is released from a height of $30 \ m$ vertically downwards. The speed of the body at which potential energy is twice that of kinetic energy is (Acceleration due to gravity $= 10 \ m \ s^{-2}$)

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