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Question

(A) The work done by a force is given by the formula $W = F \cdot s \cdot \cos(	heta)$, where $F$ is the force, $s$ is the displacement, and $	heta$

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$0 \ J$

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(A) The work done by a force is given by the formula $W = F \cdot s \cdot \cos(	heta)$, where $F$ is the force, $s$ is the displacement, and $	heta$ is the angle between the force and displacement vectors.In this case, the force of gravity acts vertically downwards $(F = mg)$.The displacement $s$ is the straight-line distance between the initial and final points.Since the initial and final points lie on the same horizontal line, the vertical displacement is $0$.Because the gravitational force acts only in the vertical direction, the work done by gravity is $W = F 	imes (	ext{vertical displacement}) = mg 	imes 0 = 0 \ J$.

An object thrown at a certain angle to the ground moves in a curved path and falls back to the ground. The initial and the final points of the path of the object lie on the same horizontal line. What is the work done by the force of gravity on the object?

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