An object weighs m_1 in a liquid of density d | vedclass

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(D) Let $V$ be the volume of the object and $d$ be its density. The apparent weight of the object in a liquid is given by the actual weight minus the

Vedclass · Accepted Answer

$d=\frac{m_1 d_2-m_2 d_1}{m_1-m_2}$

Vedclass · Answer

(D) Let $V$ be the volume of the object and $d$ be its density. The apparent weight of the object in a liquid is given by the actual weight minus the buoyant force.In the first liquid: $m_1 g = V d g - V d_1 g = V g (d - d_1) \implies m_1 = V(d - d_1) \quad (1)$In the second liquid: $m_2 g = V d g - V d_2 g = V g (d - d_2) \implies m_2 = V(d - d_2) \quad (2)$Dividing equation $(1)$ by equation $(2)$:$\frac{m_1}{m_2} = \frac{d - d_1}{d - d_2}$$m_1(d - d_2) = m_2(d - d_1)$$m_1 d - m_1 d_2 = m_2 d - m_2 d_1$$d(m_1 - m_2) = m_1 d_2 - m_2 d_1$$d = \frac{m_1 d_2 - m_2 d_1}{m_1 - m_2}$

An object weighs $m_1$ in a liquid of density $d_1$ and $m_2$ in a liquid of density $d_2$. The density $d$ of the object is

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