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Question

(D) $1$. Molisch's test is a general test for all carbohydrates.$2$. Benedict's test is used to identify reducing sugars,which possess a free aldehyde

Vedclass · Accepted Answer

Maltose

Vedclass · Answer

(D) $1$. Molisch's test is a general test for all carbohydrates.$2$. Benedict's test is used to identify reducing sugars,which possess a free aldehyde or ketone group.$3$. Seliwanoff's test is specific for ketohexoses (like fructose) and distinguishes them from aldoses.$4$. Sucrose is a non-reducing sugar (negative Benedict's test).$5$. Fructose is a ketohexose (positive Seliwanoff's test).$6$. Maltose is a reducing disaccharide (positive Benedict's test) and an aldose (negative Seliwanoff's test).$7$. Therefore,the compound is Maltose.

An organic compound gives a positive result for Molisch's test as well as Benedict's test,but it does not give a positive result for Seliwanoff's test. Most probably,it is:

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