An urn contains $10$ black and $5$ white balls. Two balls are drawn from the urn one after the other without replacement. What is the probability that both drawn balls are black?

$A$ bag $X$ contains $2$ white and $3$ black balls and another bag $Y$ contains $4$ white and $2$ black balls. One bag is selected at random and a ball is drawn from it. Then,the probability for the ball chosen to be white is:

The probability that India wins the toss is $3/4$. If it wins the toss,the probability of winning the match is $4/5$,otherwise it is $1/2$. Find the probability that India wins the match.

Urn $A$ contains $6$ white and $2$ black balls; urn $B$ contains $5$ white and $3$ black balls and urn $C$ contains $4$ white and $4$ black balls. If an urn is chosen at random and a ball is drawn at random from it, then the probability that the ball drawn is white is

If $A$ and $B$ are two independent events and $P(A)=\frac{3}{5}$ and $P(B)=\frac{2}{3}$,then $P(A' \cap B')=$

If $A$ and $B$ are two independent events such that $P(A)=0.3$,$P(B)=x$ and $P(A \cup B)=0.44$,then $x=$