Analyze the following reaction and identify t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction of styrene with $HBr$ in the absence of peroxides (or light) follows Markovnikov's rule,which is an electrophilic addition reaction,y

Vedclass · Accepted Answer

Formation of $A$ is an electrophilic addition reaction and formation of $B$ is a free radical addition reaction.

Vedclass · Answer

(A) The reaction of styrene with $HBr$ in the absence of peroxides (or light) follows Markovnikov's rule,which is an electrophilic addition reaction,yielding $1$-bromo-$1$-phenylethane $(A)$.In the presence of light $(h
u)$,the reaction follows the anti-Markovnikov addition (peroxide effect/free radical mechanism),yielding $1$-bromo-$2$-phenylethane $(B)$.Thus,the formation of $A$ is an electrophilic addition reaction,and the formation of $B$ is a free radical addition reaction.

Analyze the following reaction and identify the nature of $A$ and $B$.

Similar Questions

Identify product $A$ in the following reaction:
$4-methylcyclohexyl bromide + OH^- \xrightarrow{S_N2} A$

The reagents required for the following two-step transformation are:

In the $S_{N}2$ substitution reaction $R-Br + Cl^- \xrightarrow{DMF} R-Cl + Br^-$,which of the following will have the highest rate?

The compound added to prevent chloroform from forming phosgene gas is

What is the product formed by the reaction of $C_6H_5CH = CHCH_3$ with $HBr$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module