Anhydrous $AlCl_3$ is obtained from

Hydrolysis of $BCl_3$ gives $X$,which on treatment with sodium carbonate produces $Y$. $X$ and $Y$,respectively,are

$B(OH)_3 + NaOH \to NaBO_2 + Na[B(OH)_4] + H_2O$
How can this reaction be made to proceed in the forward direction?

Diborane reacts with ammonia to form $X$, which on heating gives $H_2$ and borazine. $X$ is

Diborane $(B_2H_6)$ reacts independently with $O_2$ and $H_2O$ to produce,respectively

In the structure of $B_2H_6$,the number of $BH_2$ groups present in one plane,and the number of $B-H$ terminal bonds,$B-B$ bonds,and $B-H-B$ bridge bonds are respectively: