Diborane reacts with ammonia to form X, which | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction of diborane $(B_2H_6)$ with ammonia $(NH_3)$ at low temperature results in the formation of an ionic adduct $X$, which is diammoniate

Vedclass · Accepted Answer

$[BH_2(NH_3)_2]^+[BH_4]^-$

Vedclass · Answer

(A) The reaction of diborane $(B_2H_6)$ with ammonia $(NH_3)$ at low temperature results in the formation of an ionic adduct $X$, which is diammoniate of diborane, $[BH_2(NH_3)_2]^+[BH_4]^-$. The chemical equation is: $B_2H_6 + 2NH_3 \longrightarrow [BH_2(NH_3)_2]^+[BH_4]^-$. Upon heating, this compound $X$ undergoes decomposition to form borazine $(B_3N_3H_6)$ and hydrogen gas $(H_2)$: $3[BH_2(NH_3)_2]^+[BH_4]^- \xrightarrow{\Delta} 2B_3N_3H_6 + 12H_2$.

Diborane reacts with ammonia to form $X$, which on heating gives $H_2$ and borazine. $X$ is

Similar Questions

For a $p$-block element,its $3d, 3s, 3p$ and $4s$ orbitals are completely filled and the differentiating electron goes to the $4p$ orbital. The element should have its atomic number in the range:

Which of the following is $NOT$ true regarding the structure of diborane $(B_2H_6)$?

Maximum number of atoms which are present in one plane of $H_3BO_3$?

Boron halides are Lewis acids because.....

$BrF_3$ self-ionizes as follows:

Vedclass Test Series

Exam Paper Generator

Online Exam Module