Identify the main product of the reaction between benzene and $1$-chloropropane in the presence of $AlCl_3$.

(D) The reaction of benzene with $1$-chloropropane in the presence of $AlCl_3$ is a Friedel-Crafts alkylation.
The initial carbocation formed is the $1^{\circ}$-propyl carbocation $(CH_3CH_2CH_2^+)$.
This $1^{\circ}$-carbocation is unstable and undergoes a $1,2$-hydride shift to form a more stable $2^{\circ}$-isopropyl carbocation $(CH_3CH^+CH_3)$.
The $2^{\circ}$-carbocation then attacks the benzene ring to form isopropylbenzene (cumene) as the major product.
Therefore,the main product is isopropylbenzene.