Anu can complete a work in 10 days. Manu is 2 | vedclass

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(C) Anu completes the work in $10$ days.Manu is $25\%$ more efficient than Anu,so Manu's time taken $= 10 	imes \frac{100}{125} = 8$ days.Sonu is $60

Vedclass · Accepted Answer

$2 \frac{6}{17}$

Vedclass · Answer

(C) Anu completes the work in $10$ days.Manu is $25\%$ more efficient than Anu,so Manu's time taken $= 10 	imes \frac{100}{125} = 8$ days.Sonu is $60\%$ more efficient than Manu,so Sonu's time taken $= 8 	imes \frac{100}{160} = 5$ days.Let the total work be $40$ units ($LCM$ of $10, 8, 5$).Efficiency of Anu $= \frac{40}{10} = 4$ units/day.Efficiency of Manu $= \frac{40}{8} = 5$ units/day.Efficiency of Sonu $= \frac{40}{5} = 8$ units/day.Combined efficiency $= 4 + 5 + 8 = 17$ units/day.Time taken by all three working together $= \frac{40}{17} = 2 \frac{6}{17}$ days.

Anu can complete a work in $10$ days. Manu is $25\%$ more efficient than Anu,and Sonu is $60\%$ more efficient than Manu. Working together,how long would they take to finish the job? (in days)

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