The area under a velocity$-$time graph is equal to the

How can you find the distance travelled by a body in uniform motion from the velocity$-$time graph?

The velocity$-$time graph of a body has a negative slope. The body is undergoing

The following table shows the position of three persons between $8.00\, am$ to $8.20\, am$.

Time	Position of Person $A$ $(km)$	Position of Person $B$ $(km)$	Position of Person $C$ $(km)$
$8.00\, am$	$0$	$0$	$0$
$8.05\, am$	$4$	$5$	$10$
$8.10\, am$	$13$	$10$	$19$
$8.15\, am$	$20$	$15$	$24$
$8.20\, am$	$25$	$20$	$27$

$(i)$ Who is moving with constant speed?
$(ii)$ Who has travelled the maximum distance between $8.00\, am$ to $8.05\, am$?
$(iii)$ Calculate the average speed of person $A$ in $km\, h^{-1}$.

"The direction in which an object moves is given by the direction of velocity of the object and not by the direction of acceleration." Give an example to justify this statement.

In your everyday life,you come across a range of motions in which
$(a)$ acceleration is in the direction of motion.
$(b)$ acceleration is against the direction of motion.
$(c)$ acceleration is uniform.
$(d)$ acceleration is non$-$uniform.
Can you identify one example each of the above type of motion?