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(C) The stability of carbocations is increased by the $+I$ effect and hyperconjugation,and decreased by the $-I$ effect.In $CH_3-CH_2-CH_2^+$ $(d)$,th

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$d > c > b > a$

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(C) The stability of carbocations is increased by the $+I$ effect and hyperconjugation,and decreased by the $-I$ effect.In $CH_3-CH_2-CH_2^+$ $(d)$,the ethyl group provides a $+I$ effect,which stabilizes the positive charge.In $F-CH_2-CH_2^+$ $(b)$ and $Br-CH_2-CH_2^+$ $(c)$,the halogens exert a $-I$ effect,which destabilizes the carbocation.Since $F$ is more electronegative than $Br$,its $-I$ effect is stronger,making $(b)$ less stable than $(c)$.$CH_3^+$ $(a)$ is a methyl carbocation,which is less stable than primary carbocations like $(d)$ and $(c)$.Therefore,the decreasing order of stability is $d > c > b > a$.

Arrange the following cations in decreasing order of their stability:
$(a)$ $CH_3^+$
$(b)$ $F-CH_2-CH_2^+$
$(c)$ $Br-CH_2-CH_2^+$
$(d)$ $CH_3-CH_2-CH_2^+$

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Arrange the following cations in decreasing order of their stability:$(a)$ $CH_3^+$$(b)$ $F-CH_2-CH_2^+$$(c)$ $Br-CH_2-CH_2^+$$(d)$ $CH_3-CH_2-CH_2^+$

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Arrange the following cations in decreasing order of their stability:
$(a)$ $CH_3^+$
$(b)$ $F-CH_2-CH_2^+$
$(c)$ $Br-CH_2-CH_2^+$
$(d)$ $CH_3-CH_2-CH_2^+$

Arrange the following carbocations in increasing order of stability:
$1. \, (CH_3)_2 - \overset{+}{C} - CH_2 - CH_3$
$2. \, (CH_3)_3 - \overset{+}{C}$
$3. \, (CH_3)_2 - \overset{+}{C} H$
$4. \, CH_3 - \overset{+}{C} H_2$
$5. \, \overset{+}{C} H_3$