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(A) The compounds are: $(i)$ Toluene $(C_6H_5CH_3)$ (ii) $m$-Dichlorobenzene (iii) $o$-Dichlorobenzene (iv) $p$-Dichlorobenzene $1$. For $p$-dichlorob

Vedclass · Accepted Answer

$iv < i < ii < iii$

Vedclass · Answer

(A) The compounds are: $(i)$ Toluene $(C_6H_5CH_3)$ (ii) $m$-Dichlorobenzene (iii) $o$-Dichlorobenzene (iv) $p$-Dichlorobenzene $1$. For $p$-dichlorobenzene (iv),the two $C-Cl$ bond dipoles are equal and opposite,so they cancel each other out,resulting in a dipole moment of $0$. $2$. For toluene $(i)$,the dipole moment is small due to the weak electron-donating effect of the $-CH_3$ group. $3$. For $m$-dichlorobenzene (ii),the angle between the two $C-Cl$ bonds is $120^{\circ}$. The resultant dipole moment is $\sqrt{\mu^2 + \mu^2 + 2\mu^2 \cos(120^{\circ})} = \mu$. $4$. For $o$-dichlorobenzene (iii),the angle between the two $C-Cl$ bonds is $60^{\circ}$. The resultant dipole moment is $\sqrt{\mu^2 + \mu^2 + 2\mu^2 \cos(60^{\circ})} = \sqrt{3}\mu$. Comparing these,the order is $iv (0) Thus,the correct option is $A$.

Arrange the following compounds in the increasing order of their dipole moment.

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