Aspirin is an acetylation product of

The product of the above Friedel-Crafts reaction is:

What is obtained when oxalic acid is dehydrated in the presence of concentrated $H_2SO_4$?

An optically active compound $'X'$ having molecular formula $C_4H_8O_3$ evolves $CO_2$ with $NaHCO_3$. $'X'$ on treatment with $LiAlH_4$ gives an achiral compound. Then $'X'$ is:

In the esterification of a carboxylic acid,the other reagent used is:

Consider the following sequence of reactions:
$2\text{-benzylbenzoic acid}$ $\xrightarrow{SOCl_2} A$ $\xrightarrow[2. H_3O^+]{1. AlCl_3} B$ $\xrightarrow{Zn-Hg, \text{conc. } HCl, \text{heat}} C$
The end product $(C)$ is: