Assertion : Alkyl iodide can be prepared by t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of alkyl chlorides or alkyl bromides with $NaI$ in acetone to form alkyl iodides is known as the $Finkelstein$ reaction.The chemical

Vedclass · Accepted Answer

If the Assertion is correct but Reason is incorrect.

Vedclass · Answer

(C) The reaction of alkyl chlorides or alkyl bromides with $NaI$ in acetone to form alkyl iodides is known as the $Finkelstein$ reaction.The chemical equation is: $R-X + NaI \xrightarrow{	ext{acetone}} R-I + NaX$ (where $X = Cl, Br$).In this reaction,$NaI$ is soluble in acetone,whereas $NaCl$ and $NaBr$ are insoluble in acetone.Because $NaCl$ or $NaBr$ precipitate out of the solution,the equilibrium shifts in the forward direction according to $Le$ $Chatelier's$ principle,facilitating the formation of alkyl iodide.Therefore,the Assertion is correct,but the Reason is incorrect because it states the solubility properties in reverse.

Assertion : Alkyl iodide can be prepared by treating alkyl chloride/bromide with $NaI$ in acetone.
Reason : $NaCl/NaBr$ are soluble in acetone while $NaI$ is not.

Similar Questions

Which reagent is not used in the Swarts reaction?

To obtain a Grignard reagent,magnesium is reacted with......?

Which of the following is incorrectly matched?
(Formation of) (Best synthesis by)

In the given reaction:
$CH_3-CH_2-COOH \xrightarrow[(ii) \ Br_2/\Delta]{(i) \ AgNO_3} [X]$
$[X]$ will be:

The method of preparation of alkyl fluoride given by the reaction $2R-Br + Hg_2F_2 \rightarrow 2R-F + Hg_2Br_2$ is known as:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion : Alkyl iodide can be prepared by treating alkyl chloride/bromide with $NaI$ in acetone.Reason : $NaCl/NaBr$ are soluble in acetone while $NaI$ is not.