Assign double bond configurations (E or Z) to | vedclass

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(C) To determine the configuration of the double bonds,we apply the Cahn-Ingold-Prelog $(CIP)$ priority rules to the substituents on each carbon of th

Vedclass · Accepted Answer

$E, E$

Vedclass · Answer

(C) To determine the configuration of the double bonds,we apply the Cahn-Ingold-Prelog $(CIP)$ priority rules to the substituents on each carbon of the double bonds.$1$. For the left double bond:- The carbon atom attached to the $-CN$ and $-CH_2NH_2$ groups has priorities: $-CN$ (atomic number of $N$ is $7$) > $-CH_2NH_2$ (atomic number of $C$ is $6$).- The other carbon atom of the double bond is attached to the cyclopentane ring and a $-CN$ group. The $-CN$ group has higher priority than the ring carbon.- Since the higher priority groups ($-CN$ on both carbons) are on opposite sides,the configuration is $E$.$2$. For the right double bond (exocyclic double bond on the ring):- One carbon is part of the ring. The substituents are the ring carbons. Comparing the paths,the path towards the substituted side has higher priority.- The other carbon of the double bond is attached to $-COOH$ and $-CH_2OH$. $-COOH$ has higher priority than $-CH_2OH$ (oxygen vs hydrogen at the first point of difference).- Based on the spatial arrangement,the higher priority groups are on opposite sides,resulting in $E$ configuration.Thus,both double bonds have $E$ configuration. The correct answer is $E, E$.

Assign double bond configurations ($E$ or $Z$) to the following structure:

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