Assuming complete ionisation,same moles of wh | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $KMnO_4$ $(Mn^{7+})$ is reduced to $Mn^{2+}$,involving $5$ electrons per mole of $KMnO_4$.For the same number of moles of the compound,the one req

Vedclass · Accepted Answer

$FeSO_4$

Vedclass · Answer

(D) $KMnO_4$ $(Mn^{7+})$ is reduced to $Mn^{2+}$,involving $5$ electrons per mole of $KMnO_4$.For the same number of moles of the compound,the one requiring the least number of electrons for oxidation will require the least amount of $KMnO_4$.$(a)$ For $FeSO_3$:$Fe^{2+} \rightarrow Fe^{3+} + 1e^-$$SO_3^{2-} \rightarrow SO_4^{2-} + 2e^-$Total $e^- = 1 + 2 = 3$$(b)$ For $FeC_2O_4$:$Fe^{2+} \rightarrow Fe^{3+} + 1e^-$$C_2O_4^{2-} \rightarrow 2CO_2 + 2e^-$Total $e^- = 1 + 2 = 3$$(c)$ For $Fe(NO_2)_2$:$Fe^{2+} \rightarrow Fe^{3+} + 1e^-$$2NO_2^- \rightarrow 2NO_3^- + 4e^-$Total $e^- = 1 + 4 = 5$$(d)$ For $FeSO_4$:$Fe^{2+} \rightarrow Fe^{3+} + 1e^-$Total $e^- = 1$Since $FeSO_4$ involves the minimum number of electrons $(1)$,it requires the least amount of $KMnO_4$.

Assuming complete ionisation,same moles of which of the following compounds will require the least amount of acidified $KMnO_4$ for complete oxidation?

Similar Questions

What is '$A$' in the following reaction?
$2Fe^{3+} + Sn^{2+} \to 2Fe^{2+} + A$

In the redox reaction
$x \ MnO + y \ PbO_2 + z \ HNO_3 \to a \ HMnO_4 + b \ Pb(NO_3)_2 + c \ H_2O$
Find the values of $x, y, z$.

How many grams of $Mg$ is required to completely reduce $100 \ mL$ of $0.1 \ M$ $NO_3^{-}$ solution using the following reaction:
$NO_3^{-} + Mg \longrightarrow Mg^{2+} + NH_3$

Which of the following is a redox reaction?

In neutral or faintly alkaline solution,$8$ moles of permanganate anion quantitatively oxidize thiosulphate anions to produce $X$ moles of a sulphur containing product. The magnitude of $X$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module