A stone is swinging in a horizontal circle 0. | vedclass

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(C) The diameter of the horizontal circle is $d = 0.8 \, m$. The amplitude $A$ of the simple harmonic motion $(SHM)$ is the radius of this circle.$A =

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$0.4 \, m, 2 \, s$

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(C) The diameter of the horizontal circle is $d = 0.8 \, m$. The amplitude $A$ of the simple harmonic motion $(SHM)$ is the radius of this circle.$A = \frac{d}{2} = \frac{0.8 \, m}{2} = 0.4 \, m$.The frequency of revolution is $f = 30 \, rev/min = \frac{30}{60} \, rev/s = 0.5 \, Hz$.The period $T$ of the $SHM$ is the same as the time taken for one complete revolution.$T = \frac{1}{f} = \frac{1}{0.5} = 2 \, s$.Alternatively,using angular velocity $\omega = \frac{2 \pi 	imes 30}{60} = \pi \, rad/s$.Since $\omega = \frac{2 \pi}{T}$,we have $\pi = \frac{2 \pi}{T}$,which gives $T = 2 \, s$.

$A$ stone is swinging in a horizontal circle $0.8 \, m$ in diameter at $30 \, rev/min$. $A$ distant horizontal light beam causes a shadow of the stone to be formed on a nearly vertical wall. The amplitude and period of the simple harmonic motion for the shadow of the stone are:

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