At 298 K,Henry's law constant for CO_2 in wa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to Henry's law,$P = K_H 	imes \chi$,where $P$ is the partial pressure of the gas,$K_H$ is Henry's law constant,and $\chi$ is the mole f

Vedclass · Accepted Answer

$5.55 	imes 10^{-2}$

Vedclass · Answer

(D) According to Henry's law,$P = K_H 	imes \chi$,where $P$ is the partial pressure of the gas,$K_H$ is Henry's law constant,and $\chi$ is the mole fraction of the gas in the solution.Given: $P = 1.67 	imes 10^2 \ kPa = 1.67 	imes 10^5 \ Pa$,$K_H = 1.67 	imes 10^8 \ Pa$.Calculating mole fraction $\chi = P / K_H = (1.67 	imes 10^5) / (1.67 	imes 10^8) = 10^{-3}$.Since the solution is dilute,the mole fraction $\chi \approx n_{CO_2} / n_{H_2O}$.For $1000 \ mL$ of water,mass $= 1000 \ g$,so $n_{H_2O} = 1000 / 18 = 55.55 \ mol$.Thus,$n_{CO_2} = \chi 	imes n_{H_2O} = 10^{-3} 	imes 55.55 = 5.555 	imes 10^{-2} \ mol$.Since the volume is $1 \ L$,the concentration is $5.55 	imes 10^{-2} \ mol \ L^{-1}$.

Gas	$K_H$ (kbar at $298 \ K$)
$CO_2$	$1.67$
$Ar$	$40.3$
$HCHO$	$1.83 \times 10^{-5}$
$CH_4$	$0.413$

At $298 \ K$,Henry's law constant for $CO_2$ in water is $1.67 \times 10^8 \ Pa$. At $298 \ K$,the quantity of $CO_2$ in $1000 \ mL$ of soda water when packed at $1.67 \times 10^2 \ kPa$ $CO_2$ pressure in $mol \ L^{-1}$ is: (water density $= 1.0 \ g \ cm^{-3}$)

Similar Questions

Observe the following data given in the table $(K_H = \text{Henry's law constant})$. The correct order of solubility of these gases is:
Gas $K_H$ (kbar at $298 \ K$)
$CO_2$ $1.67$
$Ar$ $40.3$
$HCHO$ $1.83 \times 10^{-5}$
$CH_4$ $0.413$

Choose the correct statement.

Henry's law constant for the solubility of $N_2$ gas in water at $298\, K$ is $1.0 \times 10^5\, atm$. The mole fraction of $N_2$ in air is $0.6$. The moles of $N_2$ from air dissolved in $10$ moles of water at $298\, K$ and $5\, atm$ pressure is

$(a)$ Explain the following phenomena with the help of Henry’s law.
$(i)$ Painful condition known as bends.
$(ii)$ Feeling of weakness and discomfort in breathing at high altitude.
$(b)$ Why does a soda water bottle kept at room temperature fizz on opening?

Which is the correct order for the solubility of the following compounds in $n$-octane (at identical conditions)? $I$) Cyclohexane $II$) $KCl$ $III$) $CH_3OH$ $IV$) $CH_3CN$

Vedclass Test Series

Exam Paper Generator

Online Exam Module