(B) For the reaction: $X_{(g)} + Y_{(g)} \rightleftharpoons Z_{(g)} + A_{(g)}$ Initial moles: $X = 1, Y = 1, Z = 0, A = 0$ Moles at equilibrium: $X =

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) For the reaction: $X_{(g)} + Y_{(g)} \rightleftharpoons Z_{(g)} + A_{(g)}$ Initial moles: $X = 1, Y = 1, Z = 0, A = 0$ Moles at equilibrium: $X = 1 - 0.5 = 0.5, Y = 1 - 0.5 = 0.5, Z = 0.5, A = 0.5$ Since volume $V = 1 \ L$,concentration $[C] = \text{moles}/V$ $K_c = \frac{[Z][A]}{[X][Y]} = \frac{0.5 \times 0.5}{0.5 \times 0.5} = 1.0$

Class 11 Chemistry 6-1.Equilibrium (Chemical Equilibrium)Kp and Kc Relationship

Medium

At $T(K)$,when $1 \ mol$ of $X$ and $1 \ mol$ of $Y$ are heated in a $1 \ L$ flask,$0.5 \ mol$ of $Z$ is formed at equilibrium. The $K_c$ value for the reaction $X_{(g)} + Y_{(g)} \rightleftharpoons Z_{(g)} + A_{(g)}$ is:

TS EAMCET 2023 All TS EAMCET

A
$0.5$
B
$1.0$
C
$0.75$
D
$0.82$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

6-1.Equilibrium (Chemical Equilibrium)

Subtopic

Kp and Kc Relationship

Previous Year

TS EAMCET 2023 Paper All TS EAMCET years →

At $1100 \ K$ temperature,$CaCO_{3(s)}$ and $CaO_{(s)}$ are in equilibrium. The pressure of $CO_{2(g)}$ is $2.0 \times 10^5 \ Pa$.
Find the equilibrium constant $(K_p)$ for the reaction: $CaCO_{3(s)} \rightleftharpoons CaO_{(s)} + CO_{2(g)}$

Medium

View Solution

For the reaction,$PCl_{3(g)} + Cl_{2(g)} \rightleftharpoons PCl_{5(g)}$,the value of $K_c$ at $250 \ ^oC$ is $26$. The value of $K_p$ at this temperature will be:

Medium

View Solution

For the reaction $CO_{(g)} + 1/2 O_{2(g)} \rightleftharpoons CO_{2(g)}$,the value of $K_p/K_c$ is .....

Easy

View Solution

For the reaction,$2A_{(g)} \rightleftharpoons 3C_{(g)} + D_{(g)}$,the value of $K_c$ will be equal to:

Medium

View Solution

In which of the following reactions is $K_p = K_c$?

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

At $T(K)$,when $1 \ mol$ of $X$ and $1 \ mol$ of $Y$ are heated in a $1 \ L$ flask,$0.5 \ mol$ of $Z$ is formed at equilibrium. The $K_c$ value for the reaction $X_{(g)} + Y_{(g)} \rightleftharpoons Z_{(g)} + A_{(g)}$ is:

Similar Questions

At $1100 \ K$ temperature,$CaCO_{3(s)}$ and $CaO_{(s)}$ are in equilibrium. The pressure of $CO_{2(g)}$ is $2.0 \times 10^5 \ Pa$.Find the equilibrium constant $(K_p)$ for the reaction: $CaCO_{3(s)} \rightleftharpoons CaO_{(s)} + CO_{2(g)}$

For the reaction,$PCl_{3(g)} + Cl_{2(g)} \rightleftharpoons PCl_{5(g)}$,the value of $K_c$ at $250 \ ^oC$ is $26$. The value of $K_p$ at this temperature will be:

For the reaction $CO_{(g)} + 1/2 O_{2(g)} \rightleftharpoons CO_{2(g)}$,the value of $K_p/K_c$ is .....

For the reaction,$2A_{(g)} \rightleftharpoons 3C_{(g)} + D_{(g)}$,the value of $K_c$ will be equal to:

In which of the following reactions is $K_p = K_c$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

At $1100 \ K$ temperature,$CaCO_{3(s)}$ and $CaO_{(s)}$ are in equilibrium. The pressure of $CO_{2(g)}$ is $2.0 \times 10^5 \ Pa$.
Find the equilibrium constant $(K_p)$ for the reaction: $CaCO_{3(s)} \rightleftharpoons CaO_{(s)} + CO_{2(g)}$