At a certain place, the angle of dip is 60^{c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given:Horizontal component of earth's magnetic field, $B_H = 0.8 	imes 10^{-4} \,T$Angle of dip, $	heta = 60^{\circ}$Let the earth's total magne

Vedclass · Accepted Answer

$1.6 	imes 10^{-4} \,T$

Vedclass · Answer

(D) Given:Horizontal component of earth's magnetic field, $B_H = 0.8 	imes 10^{-4} \,T$Angle of dip, $	heta = 60^{\circ}$Let the earth's total magnetic field be $B_e$.We know that the horizontal component of the earth's magnetic field is related to the total magnetic field by the formula:$B_H = B_e \cos 	heta$Substituting the given values:$0.8 	imes 10^{-4} = B_e \cos 60^{\circ}$Since $\cos 60^{\circ} = 0.5$ or $\frac{1}{2}$, we have:$0.8 	imes 10^{-4} = B_e 	imes 0.5$Solving for $B_e$:$B_e = \frac{0.8 	imes 10^{-4}}{0.5}$$B_e = 1.6 	imes 10^{-4} \,T$Thus, the earth's overall magnetic field is $1.6 	imes 10^{-4} \,T$.

At a certain place, the angle of dip is $60^{\circ}$ and the horizontal component of the earth's magnetic field $(B_H)$ is $0.8 \times 10^{-4} \,T$. The earth's overall magnetic field is

Similar Questions

If the magnetic declination at a place is known to be $15^{\circ} \, E$,and a compass needle points as shown in the figure,then the geographic north is represented by which numbered direction?

Explain magnetic declination.

The angle of dip is the angle

At a given place on the Earth,the angle between the Magnetic Meridian and the Geographic Meridian is called . . . . . . .

Name the elements of the earth's magnetic field.

Vedclass Test Series

Exam Paper Generator

Online Exam Module