At a certain temperature,the degrees of freed | vedclass

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(A) Given,degrees of freedom $f = 8$.Work done at constant pressure is given by $W = n R \Delta T = 150 \; J$.The heat absorbed at constant pressure i

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$750$

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(A) Given,degrees of freedom $f = 8$.Work done at constant pressure is given by $W = n R \Delta T = 150 \; J$.The heat absorbed at constant pressure is given by $Q = n C_p \Delta T$.We know that $C_p = \left( \frac{f}{2} + 1 ight) R$.Substituting this into the heat equation: $Q = n \left( \frac{f}{2} + 1 ight) R \Delta T$.Since $W = n R \Delta T = 150 \; J$,we have $Q = \left( \frac{f}{2} + 1 ight) W$.Substituting $f = 8$ and $W = 150 \; J$:$Q = \left( \frac{8}{2} + 1 ight) 	imes 150 = (4 + 1) 	imes 150 = 5 	imes 150 = 750 \; J$.

At a certain temperature,the degrees of freedom per molecule for a gas is $8$. The gas performs $150 \; J$ of work when it expands under constant pressure. The amount of heat absorbed by the gas will be $..... \; J$.

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