At high temperature and low pressure,the Vander Waal's equation is reduced to

  • A
    $(p + \frac{a}{V_m^2})(V_m) = RT$
  • B
    $p V_m = RT$
  • C
    $p (V_m - b) = RT$
  • D
    $(p + \frac{a}{V_m^2})(V_m - b) = RT$

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Similar Questions

Consider the van der Waals constants,$a$ and $b$,for the following gases:
Gas $Ar$ $Ne$ $Kr$ $Xe$
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$b / (10^{-2} \ dm^3 \ mol^{-1})$ $3.2$ $1.7$ $1.0$ $5.0$

Which gas is expected to have the highest critical temperature?

Pressure exerted by $1 \, mole$ of methane in a $0.25 \, L$ container at $300 \, K$ using van der Waals equation is ............... $atm$ (given $a = 2.253 \, atm \, L^2 \, mol^{-2}, b = 0.0428 \, L \, mol^{-1}$):

For real gases,the van der Waals equation is written as $\left( p + \frac{a n^2}{V^2} \right) (V - nb) = nRT$,where $a$ and $b$ are van der Waals constants. Two sets of gases are:
$(I)$ $O_2, CO_2, H_2, He$
$(II)$ $CH_4, O_2, H_2$
The gases given in set-$I$ are arranged in increasing order of $b$,and the gases given in set-$II$ are arranged in decreasing order of $a$. Select the correct order from the following:

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