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(B) For a concave mirror,magnification $m = -v/u$. Given $m = -2$. Substituting this,$-2 = -v/u$,which implies $v = 2u$. According to the mirror formu

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Between the principal focus and the center of curvature

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(B) For a concave mirror,magnification $m = -v/u$. Given $m = -2$. Substituting this,$-2 = -v/u$,which implies $v = 2u$. According to the mirror formula,$1/f = 1/v + 1/u$. Substituting $v = 2u$,we get $1/f = 1/(2u) + 1/u = 3/(2u)$. This gives $u = 1.5f$. Since the focal length $f$ is between the pole and the center of curvature $(2f)$,an object placed at $1.5f$ lies between the principal focus $(F)$ and the center of curvature $(C)$. Thus,the correct position is between the principal focus and the center of curvature.

At what position should an object be placed in front of a concave mirror to obtain a magnification of $(- 2)$?

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