At what temperature will the root mean square | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The root mean square speed $(u_{rms})$ is given by the formula $u_{rms} = \sqrt{\frac{3RT}{M}}$.For the speeds to be equal,$\sqrt{\frac{3RT_1}{M_1

Vedclass · Accepted Answer

$177$

Vedclass · Answer

(B) The root mean square speed $(u_{rms})$ is given by the formula $u_{rms} = \sqrt{\frac{3RT}{M}}$.For the speeds to be equal,$\sqrt{\frac{3RT_1}{M_1}} = \sqrt{\frac{3RT_2}{M_2}}$,which simplifies to $\frac{T_1}{M_1} = \frac{T_2}{M_2}$.Here,$M_1$ (molar mass of $O_3$) = $48 \, g/mol$,$M_2$ (molar mass of $O_2$) = $32 \, g/mol$,and $T_2 = 27 + 273 = 300 \, K$.Substituting the values: $\frac{T_1}{48} = \frac{300}{32}$.$T_1 = \frac{300 	imes 48}{32} = 300 	imes 1.5 = 450 \, K$.Converting back to Celsius: $450 - 273 = 177 \, ^oC$.

At what temperature will the root mean square speed of ozone $(O_3)$ be equal to the root mean square speed of oxygen $(O_2)$ at $27 \, ^oC$?

Similar Questions

Name the method of asexual reproduction in fungi.

The roots that originate from the base of the stem are called:

If $z = \frac{y}{x} \left[ \sin \frac{x}{y} + \cos \left( 1 + \frac{y}{x} \right) \right]$,then $x \frac{\partial z}{\partial x}$ is equal to

Identify the incorrect pair from the following:

An aqueous solution of sodium carbonate is alkaline. This is because sodium carbonate is a salt of which of the following?

Vedclass Test Series

Exam Paper Generator

Online Exam Module