Atomic weight of an element is $x$. The actual mass of one atom of that element is

  • A
    $x \ g$
  • B
    $x \ amu$
  • C
    $x \times 6.023 \times 10^{23} \ amu$
  • D
    $\frac{x}{6.023 \times 10^{23}} \ amu$

Explore More

Similar Questions

What is the mass of one molecule of the compound $C_{60}H_{122}$ in grams?

In order to prepare one litre of a $1 \ N$ (normal) solution of $KMnO_4$,how many grams of $KMnO_4$ are required if the solution is to be used in an acidic medium for oxidation?

Difficult
View Solution

$0.126 \ g$ of an acid requires $20 \ mL$ of $0.1 \ N$ $NaOH$ for complete neutralization. The equivalent weight of the acid is:

Calculate the milli-equivalents of:
$(a) \, Ca(OH)_2$ in $74 \, g$
$(b) \, NaOH$ in $20 \, g$ respectively.

Difficult
View Solution

If the mass table of atomic weights were established with oxygen atom assigned a value of $100,$ the atomic weight of carbon would be

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo