0.126 g of an acid requires 20 mL of 0.1 N | vedclass

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Question

(D) At the equivalence point,the number of equivalents of acid equals the number of equivalents of base.Number of equivalents of $NaOH = N 	imes V

Vedclass · Accepted Answer

$63$

Vedclass · Answer

(D) At the equivalence point,the number of equivalents of acid equals the number of equivalents of base.Number of equivalents of $NaOH = N 	imes V 	ext{ (in Liters)} = 0.1 	imes \frac{20}{1000} = 0.002 	ext{ equivalents}$.Since the acid is completely neutralized,the number of equivalents of acid is also $0.002$.Equivalent weight $= \frac{	ext{Mass of acid}}{	ext{Number of equivalents}} = \frac{0.126 \ g}{0.002} = 63 \ g/eq$.

$0.126 \ g$ of an acid requires $20 \ mL$ of $0.1 \ N$ $NaOH$ for complete neutralization. The equivalent weight of the acid is:

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