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(D) The atomic mass of an atom is given by the sum of the number of protons and neutrons,as the mass of electrons is negligible.For $_6C^{12}$,the num

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Be reduced by $25\%$

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(D) The atomic mass of an atom is given by the sum of the number of protons and neutrons,as the mass of electrons is negligible.For $_6C^{12}$,the number of protons is $6$ and the number of neutrons is $6$.Original atomic mass $\approx 6 	ext{ (protons)} + 6 	ext{ (neutrons)} = 12 	ext{ amu}$.If the mass of neutrons is halved,the new mass contribution from neutrons is $6 	imes 0.5 = 3 	ext{ amu}$.The mass of electrons is negligible,so doubling it does not affect the atomic mass.New atomic mass $\approx 6 	ext{ (protons)} + 3 	ext{ (neutrons)} = 9 	ext{ amu}$.Percentage reduction $= \frac{12 - 9}{12} 	imes 100 = \frac{3}{12} 	imes 100 = 25\%$.Thus,the atomic mass is reduced by $25\%$.

Atoms consist of protons,neutrons,and electrons. If the mass of neutrons were made half and the mass of electrons were made two times their actual masses,then the atomic mass of $_6C^{12}$ would:

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