Balance the following chemical equation:Fe(s) | vedclass

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(A) To balance the equation $Fe(s) + H_2O(g) \rightarrow Fe_3O_4(s) + H_2(g)$:$1$. Balance $Fe$: There are $3$ atoms of $Fe$ on the right side,so plac

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$3Fe(s) + 4H_2O(g) \rightarrow Fe_3O_4(s) + 4H_2(g)$

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(A) To balance the equation $Fe(s) + H_2O(g) ightarrow Fe_3O_4(s) + H_2(g)$:$1$. Balance $Fe$: There are $3$ atoms of $Fe$ on the right side,so place a coefficient of $3$ before $Fe$ on the left side: $3Fe + H_2O ightarrow Fe_3O_4 + H_2$.$2$. Balance $O$: There are $4$ atoms of $O$ on the right side,so place a coefficient of $4$ before $H_2O$ on the left side: $3Fe + 4H_2O ightarrow Fe_3O_4 + H_2$.$3$. Balance $H$: Now there are $8$ atoms of $H$ on the left side $(4 	imes 2)$,so place a coefficient of $4$ before $H_2$ on the right side: $3Fe(s) + 4H_2O(g) ightarrow Fe_3O_4(s) + 4H_2(g)$.The equation is now balanced.

Balance the following chemical equation:
$Fe(s) + H_2O(g) \rightarrow Fe_3O_4(s) + H_2(g)$

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Balance the following chemical equation:$Fe(s) + H_2O(g) \rightarrow Fe_3O_4(s) + H_2(g)$