Benzene reacts with n-propyl chloride in the | vedclass

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(B) The reaction of benzene with $n-$propyl chloride in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts alkylation reaction. During this reacti

Vedclass · Accepted Answer

Isopropylbenzene

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(B) The reaction of benzene with $n-$propyl chloride in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts alkylation reaction. During this reaction,the $n-$propyl carbocation $(CH_3CH_2CH_2^+)$ formed initially undergoes a $1,2-$hydride shift to form a more stable secondary isopropyl carbocation $(CH_3CH^+CH_3)$. This secondary carbocation then attacks the benzene ring to form isopropylbenzene (cumene) as the major product. Therefore,the correct option is $B$.

Benzene reacts with $n-$propyl chloride in the presence of anhydrous $AlCl_3$ to give predominantly :

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