The Boolean relation at the output stage Y fo | vedclass

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(C) The circuit consists of two switches $A$ and $B$ connected to diodes,which act as an $OR$ gate input stage. When either switch $A$ or $B$ is close

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$\overline{A} \cdot \overline{B}$

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(C) The circuit consists of two switches $A$ and $B$ connected to diodes,which act as an $OR$ gate input stage. When either switch $A$ or $B$ is closed (logic $1$),the base of the $NPN$ transistor receives a high voltage,causing it to conduct. When the transistor conducts,the collector voltage drops to near $0 \ V$ (logic $0$). If both switches are open (logic $0$),the base is grounded through the resistor,the transistor is in cutoff $(OFF)$,and the output $Y$ is pulled up to $+5 \ V$ (logic $1$). This behavior corresponds to a $NOR$ gate,where $Y = \overline{A+B}$. According to De Morgan's theorem,$\overline{A+B} = \overline{A} \cdot \overline{B}$.$A$$B$$Y$$0$$0$$1$$1$$0$$0$$0$$1$$0$$1$$1$$0$

The Boolean relation at the output stage $Y$ for the following circuit is:

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