Both acetaldehyde and acetone (individually) | vedclass

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(B) To determine which reactions both acetaldehyde $(CH_3CHO)$ and acetone $(CH_3COCH_3)$ undergo,we analyze each reaction:						$S.No$. Name of React

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$A, C$ and $E$ only

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(B) To determine which reactions both acetaldehyde $(CH_3CHO)$ and acetone $(CH_3COCH_3)$ undergo,we analyze each reaction:						$S.No$. Name of Reaction			Acetaldehyde $(CH_3CHO)$ | Acetone $(CH_3COCH_3)$							$1$. Iodoform reaction			Positive | Positive							$2$. Cannizzaro reaction			Negative | Negative							$3$. Aldol condensation			Positive | Positive							$4$. Tollen's test			Positive | Negative							$5$. Clemmensen reduction			Positive | Positive			$1$. Iodoform reaction $(A)$: Both contain the $CH_3CO-$ group,so both give a positive test.$2$. Cannizzaro reaction $(B)$: Neither has an $\alpha$-hydrogen,so neither undergoes this reaction.$3$. Aldol condensation $(C)$: Both have $\alpha$-hydrogens,so both undergo this reaction.$4$. Tollen's test $(D)$: Only aldehydes give a positive test; acetone (a ketone) does not.$5$. Clemmensen reduction $(E)$: Both aldehydes and ketones undergo this reduction.Therefore,both compounds undergo reactions $A, C$,and $E$.

Column-$I$ (Reactants)	Column-$II$ (Major Product)
$A$. $HCHO \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$i$. $C_6H_5CHOHCH_3$
$B$. $C_6H_5CHO \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$ii$. $(CH_3)_3COH$
$C$. $CH_3COCH_3 \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$iii$. $CH_3CHOHCH_3$
$D$. $CH_3CHO \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$iv$. $CH_3CH_2OH$

Both acetaldehyde and acetone (individually) undergo which of the following reactions?
$A$. Iodoform Reaction
$B$. Cannizzaro Reaction
$C$. Aldol condensation
$D$. Tollen's Test
$E$. Clemmensen Reduction
Choose the correct answer from the options given below:

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Both acetaldehyde and acetone (individually) undergo which of the following reactions?$A$. Iodoform Reaction$B$. Cannizzaro Reaction$C$. Aldol condensation$D$. Tollen's Test$E$. Clemmensen ReductionChoose the correct answer from the options given below: