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(D) Colour blindness is an $X$-linked recessive disorder.Let the normal vision allele be $X^C$ and the colourblind allele be $X^c$.Since the husband h

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(D) Colour blindness is an $X$-linked recessive disorder.Let the normal vision allele be $X^C$ and the colourblind allele be $X^c$.Since the husband has normal vision,his genotype is $X^CY$.Since his father was colourblind,he inherited his $Y$ chromosome from his father and his $X^C$ chromosome from his mother.Since the wife has normal vision but her father was colourblind,she must be a carrier of the trait. Her genotype is $X^CX^c$.When we cross the husband $(X^CY)$ and the wife $(X^CX^c)$:Possible genotypes for their children are $X^CX^C$ (normal daughter),$X^CX^c$ (carrier daughter),$X^CY$ (normal son),and $X^cY$ (colourblind son).For a daughter to be colourblind,she must have the genotype $X^cX^c$.Since the father is $X^CY$,he can only pass the $X^C$ allele to his daughters.Therefore,the probability of their daughter being colourblind is $0\, \%$.

Both husband and wife have normal vision,though their fathers were colourblind and mothers did not have any gene for colour blindness. The probability of their daughter becoming colourblind is

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