Box $A$ contains $25$ slips of which $19$ are marked $Rs. 1$ and others are marked $Rs. 5$ each. Box $B$ contains $50$ slips of which $45$ are marked $Rs. 1$ each and others are marked $Rs. 13$ each. Slips of both boxes are poured into a third box and reshuffled. $A$ slip is drawn at random. What is the probability that it is marked other than $Rs. 1$?
- A$\frac{45}{75}$
- B$\frac{35}{75}$
- C$\frac{15}{75}$
- D$\frac{11}{75}$
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