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$But-1-ene \xrightarrow[(ii) NaBH_4]{(i) (CH_3COO)_2Hg/H_2O} ?$
The product in the above reaction is:
The product in the above reaction is:
- A$CH_3-CH_2-CH_2-CH_2-OH$
- B$CH_3-CH_2-CH(OH)-CH_3$
- C$CH_3=CH_2-CH(OH)-CH_3$
- D$CH_3-CH_2=C(OH)-CH_3$
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