By taking $\sqrt{a \pm i b}=x \pm i y, x>0$,if we get $\frac{\sqrt{21+12 \sqrt{2} i}}{\sqrt{21-12 \sqrt{2} i}}=a+i b$,then $\frac{b}{a}=$

  • A
    $\frac{4 \sqrt{2}}{7}$
  • B
    $\frac{12 \sqrt{2}}{17}$
  • C
    $\frac{4 \sqrt{3}}{7}$
  • D
    $\frac{12 \sqrt{3}}{17}$

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