Calculate the amount of $KCl$ $(MW=74.5 \ g \ mol^{-1})$ required to depress the freezing point of $500 \ g$ of water by $2 \ K$ (in $g$)? $(K_f=1.86 \ K \ kg \ mol^{-1})$

  • A
    $10.0$
  • B
    $40.0$
  • C
    $20.0$
  • D
    $35.0$

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