Calculate the energy of half a mole of photon | vedclass

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Question

(B) The energy of a single photon is given by $E = h 
u$,where $h = 6.626 	imes 10^{-34} \ J \ s$ and $
u = 3 	imes 10^{12} \ Hz$. Energy of one p

Vedclass · Accepted Answer

$0.598 \ kJ \ mol^{-1}$

Vedclass · Answer

(B) The energy of a single photon is given by $E = h 
u$,where $h = 6.626 	imes 10^{-34} \ J \ s$ and $
u = 3 	imes 10^{12} \ Hz$. Energy of one photon $= 6.626 	imes 10^{-34} 	imes 3 	imes 10^{12} = 1.9878 	imes 10^{-21} \ J$. One mole of photons contains $N_A = 6.022 	imes 10^{23}$ photons. Therefore,half a mole of photons contains $\frac{1}{2} 	imes 6.022 	imes 10^{23} = 3.011 	imes 10^{23}$ photons. Total energy for half a mole $= (1.9878 	imes 10^{-21} \ J) 	imes (3.011 	imes 10^{23}) = 598.5 \ J \approx 0.598 \ kJ$. Thus,the energy is $0.598 \ kJ \ mol^{-1}$. Hence,the correct option is $(B)$.

Calculate the energy of half a mole of photons of a radiation with a frequency of $3 \times 10^{12} \ Hz$.

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